Tuesday, October 18, 2011

Blog 10 Due Monday Oct 24 10:00 pm

In a species of plants, axial flowers are dominant to terminal flowers and the trait for height is incompletely dominant. A medium height plant with axial flowers (double heterozygote) is crossed with another double heterozygote plant. What are the genotypic and phenotypic ratio of the offspring?
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14 comments:

  1. AregOctober 23, 2011 at 7:22 PM

    Axial - A
    Terminal – a
    T1 – tall
    T2 – short

    Aa x T1 T2 combined with Aa x T1 T2
    their offspring will be

    A T1 = Axial tall
    A T1 T2 = Axial medium height
    A T1 T2 = Axial medium height
    a T2 = terminal short

    25% axial/tall
    50% axial/medium height
    25% terminal short

    ReplyDelete
  2. AnonymousOctober 23, 2011 at 9:01 PM

    A- Axial T- tall
    a-Terminal t- short

    Aa*Tt combined with Aa*Tt in a punnet square.

    Results will be
    1/4 (25%)- Axial/tall
    2/4 (50%)- Axial/Medium height
    1/4 (25%)- Terminal/Short

    ReplyDelete
  3. lara kOctober 23, 2011 at 9:41 PM

    A=axial
    a=terminal
    T1=tall
    T2=short
    Aa x T1T2 with Aa x T1T2= offspring will have the following genotyoes
    AT1=axial tall 25%
    2 AT1T2= axial medium height 50%
    aT2=terminal short 25%

    ReplyDelete
  4. ArteenOctober 23, 2011 at 10:59 PM

    A-axial
    a-terminal
    T-tall
    t-short

    AaTt X AaTt

    Phenotypes:
    Axial Tall -19%
    Axial medium -38%
    Axial short -19%
    terminal Tall -6%
    terminal medium -12%
    terminal short -6%

    ReplyDelete
  5. ArteenOctober 23, 2011 at 11:03 PM

    Genotypes:
    AATT- 1/16
    AATt- 2/16
    AAtt- 1/16

    AaTT- 2/16
    AaTt- 4/16
    Aatt- 2/16

    aaTT- 1/16
    aaTt- 2/16
    aatt- 1/16

    ReplyDelete
  6. AnonymousOctober 24, 2011 at 8:06 AM

    This comment has been removed by the author.

    ReplyDelete
  7. Mr. POctober 24, 2011 at 2:44 PM

    Alex, you are partially right but check your math. Arleen you don't have the phenotypic ratios. The rest of you need to try again.

    ReplyDelete
  8. ArteenOctober 24, 2011 at 5:02 PM

    Phenotypic ratios:
    axial tall - 3/16
    axial medium - 3/8
    axial short - 3/16
    terminal tall - 1/16
    terminal medium - 1/8
    terminal short - 1/16

    ReplyDelete
  9. ShawntOctober 24, 2011 at 5:32 PM

    A- Axial
    a- Terminal
    T- Tall
    t- Short

    Genotypes:
    AATT- 1/16
    AATt- 2/16
    AAtt- 1/16
    AaTT- 2/16
    AaTt- 4/16
    Aatt- 2/16
    aaTT- 1/16
    aaTt- 2/16
    aatt- 1/16

    Phenotype:

    Axial Medium- 37.5%
    Axial Short- 18.75%
    Axial Tall- 18.75%
    Terminal Medium- 12.5%
    Terminal Short- 6.25%
    Terminal Tall- 6.25%

    ReplyDelete
  10. Lynna OhanianOctober 24, 2011 at 9:28 PM

    A=axial
    a=terminal
    T=tall
    t=short

    Genotypes:
    1/16 aatt
    1/16 AATT
    1/16 aaTT
    1/16 AAtt
    1/8 AATt
    1/8 AaTT
    1/8 Aatt
    1/8 aaTt
    1/4 AaTt

    Phenotypes:
    Axial Tall - 3/16= 18.75%
    Axial medium -6/16= 37.5%
    Axial short -3/16= 18.75%
    terminal Tall - 1/16=6.25%
    terminal medium -2/16= 12.5%
    terminal short -1/16= 6.25

    ReplyDelete
  11. sevana nourianOctober 24, 2011 at 9:39 PM

    A- Axial
    a- Terminal
    T- Tall
    t- Short

    Genotypes:
    AATT- 1/16
    AATt- 2/16
    AAtt- 1/16
    AaTT- 2/16
    AaTt- 4/16
    Aatt- 2/16
    aaTT- 1/16
    aaTt- 2/16
    aatt- 1/16

    Phenotype:

    Axial Medium- 37.5%
    Axial Short- 18.75%
    Axial Tall- 18.75%
    Terminal Medium- 12.5%
    Terminal Short- 6.25%
    Terminal Tall- 6.25%

    ReplyDelete
  12. Farah KandahOctober 25, 2011 at 7:19 AM

    A- Axial
    a- Terminal
    T- Tall
    t- Short
    Genotypes=
    AATT - 1/16
    AATt - 2/16
    AAtt - 1/16
    AaTT - 2/16
    aaTT - 1/16
    aatt - 1/16
    AaTt - 4/16

    Phenotype=
    Axial Medium - 37.5%
    Axial Short = 18.75%
    Axial Tall = 18.75%
    Terminal Medium = 12.5%
    Terminal Short = 6.25%
    Terminal Tall = 6.25%

    ReplyDelete
  13. AnonymousOctober 25, 2011 at 8:27 AM

    A - axial
    a - terminal
    T - tall
    t - short
    AaTt x AaTt


    Phenotypes:

    axial tall - 18.75%
    axial medium - 37.5%
    axial short - 18.75%
    terminal tall - 6.25%
    terminal medium - 12.5%
    terminal short - 6.25%


    Genotypes:

    AATT - 1/16
    AATt - 1/8
    AAtt - 1/16

    AaTT - 1/8
    AaTt - 1/4
    Aatt - 1/8

    aaTT - 1/16
    aaTt - 1/8
    aatt - 1/16

    ReplyDelete
  14. AregOctober 25, 2011 at 6:47 PM

    A- Axial
    a- Terminal
    T- Tall
    t- Short
    Tt- medium

    AaTt X AaTt


    Phenotypes:
    Axial Medium - 37.5%
    Axial Short = 18.75%
    Axial Tall = 18.75%
    Terminal Medium = 12.5%
    Terminal Short = 6.25%
    Terminal Tall = 6.25%

    Genotypes:
    AATT- 1/16
    AATt- 2/16
    AAtt- 1/16
    AaTT- 2/16
    AaTt- 4/16
    Aatt- 2/16
    aaTT- 1/16
    aaTt- 2/16
    aatt- 1/16

    ReplyDelete

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